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=-11H^2+330H
We move all terms to the left:
-(-11H^2+330H)=0
We get rid of parentheses
11H^2-330H=0
a = 11; b = -330; c = 0;
Δ = b2-4ac
Δ = -3302-4·11·0
Δ = 108900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{108900}=330$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-330)-330}{2*11}=\frac{0}{22} =0 $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-330)+330}{2*11}=\frac{660}{22} =30 $
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